8[z-12]=3[2z+4]

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Solution for 8[z-12]=3[2z+4] equation:


Simplifying
8[z + -12] = 3[2z + 4]

Reorder the terms:
8[-12 + z] = 3[2z + 4]
[-12 * 8 + z * 8] = 3[2z + 4]
[-96 + 8z] = 3[2z + 4]

Reorder the terms:
-96 + 8z = 3[4 + 2z]
-96 + 8z = [4 * 3 + 2z * 3]
-96 + 8z = [12 + 6z]

Solving
-96 + 8z = 12 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
-96 + 8z + -6z = 12 + 6z + -6z

Combine like terms: 8z + -6z = 2z
-96 + 2z = 12 + 6z + -6z

Combine like terms: 6z + -6z = 0
-96 + 2z = 12 + 0
-96 + 2z = 12

Add '96' to each side of the equation.
-96 + 96 + 2z = 12 + 96

Combine like terms: -96 + 96 = 0
0 + 2z = 12 + 96
2z = 12 + 96

Combine like terms: 12 + 96 = 108
2z = 108

Divide each side by '2'.
z = 54

Simplifying
z = 54

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